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Make sure you all come to a consensus of the correct answers for each. Make sure you handed in all homework assignments from previous days. Go through the rest of this Powerpoint. Try your best on the homework at the end of this Powerpoint. I will go over it in more detail in class on Monday. If you get stuck on any, save them for Monday and we ll work on them as a group.P, 3        Bond Energy  To illustrate, let s estimate the heat of reaction for reaction between methane and chlorine gas. 4eZc   /  ` 33` Sf3f` 33g` f` www3PP` ZXdbmo` \ғ3y`Ӣ` 3f3ff` 3f3FKf` hk]wwwfܹ` ff>>\`Y{ff` R>&- {p_/̴>?" dd@,|?" dd@   " @ ` n?" dd@   @@``PR    @ ` ` p>> 4l(  4 4 6I  `}  T Click to edit Master title style! ! 4 0L  `  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S 4 0(N ^ `  @*" 4 0X ^   B*" 4 0 b ^ `  B*"H 4 0޽h ? 3380___PPT10.   1_Default Design 0 zr$ (  $ $ 0 P: P   : P*   $ 0W:    : R*  d $ c $ ?  : $ 0]:  0 : RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S $ 6+B#style.visibility<*8%(D' =-s6Bwipe(left)*<3<*8D' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*8%(D' =-s6Bwipe(down)*<3<*8D' =%(D9' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*8%(D' =-u6Bwipe(right)*<3<*8DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*8I%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*8ID-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*8ID' P=1:B solid*a3>Bfill.type<*8ID' =%(dDc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*8IW%(D' =-g6B fade*<3<*8IWD' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*8IWD' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*8IWD' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*8W%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*8WD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*8WD' P=1:B solid*a3>Bfill.type<*8W+ t    <J (  < < 0  ,$D 0 DThe strength of a bond is also related to it s stability. Consider N2 versus Cl2.R(2:# 'o/o 'o/o'oB < ZDo?"pPp,$@ 0B < ZDo?"P,$@ 0B < ZDo?"P,$@ 0  < Z ?"0:,$ 0 AN$0(#(  < Z ?"+:,$ 0 AN$0(#(B < ZDo?"p,p,$@  0(  < Zt" ?":,$  0 \Cl$0(#((  < Z\- ?" 4:,$  0 \Cl$0(#(8  < 0`6U,$D  0 <Bond Length 1.10 A Bond Enthalpy 941 KJ / mol More StableL= ## ##8  < 0# U,$D 0 <Bond Length 1.96 A Bond Enthalpy 242 KJ / mol Less StableL= ## ##H < 0޽h ? 33gg___PPT10f. pF+?x~De' = @B De' = @BA?%,( < +O%,( < +D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*<:%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*<:D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*<:D' P=1:B solid*a3>Bfill.type<*<:D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*<:R%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*<:RD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*<:RD' P=1:B solid*a3>Bfill.type<*<:RD' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<Dp' =A@BB/BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<Dp' =A@BB/BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<D' =%(D ' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*<%(D' =-g6B fade*<3<*<D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*<D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*<Dp' =A@BB/BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* <%(D' =-g6B fade*<3<* <D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <Dp' =A@BB/BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* <%(D' =-g6B fade*<3<* <D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <Dd ' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* < %(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* < D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* < D' P=1:B solid*a3>Bfill.type<* < D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* < %(D' =-g6B fade*<3<* < D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* < D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* < Dd ' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* < %(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* < D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* < D' P=1:B solid*a3>Bfill.type<* < D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* < %(D' =-g6B fade*<3<* < D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* < D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* < D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* <#%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* <#D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* <#D' P=1:B solid*a3>Bfill.type<* <#D' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* <#0%(D' =-g6B fade*<3<* <#0D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <#0D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <#0D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* <#%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* <#D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* <#D' P=1:B solid*a3>Bfill.type<* <#D' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* <#0%(D' =-g6B fade*<3<* <#0D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <#0D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <#0D' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* <1=%(D' =-g6B fade*<3<* <1=D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <1=D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <1=D' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* <1=%(D' =-g6B fade*<3<* <1=D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* <1=D' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* <1=++0+< ++0+< ++0+ < ++0+ < + @1(  @1 @ 0hS,$D 0 A*Bond enthalpies are determined experimentally using calorimetry.B(2B#5  @ 0|v*,$D 0 ,*Determining bond enthalpies for diatomic molecules is a straight forward experimental process. *When dealing with large molecules, individual bond enthalpies can be calculated by considering the average of each bond in the molecule Example:(2#H @ 0޽h ? 33___PPT10. lxB+d#-D' = @B De' = @BA?%,( < +O%,( < +D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*@B%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*@BD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*@BD' P=1:B solid*a3>Bfill.type<*@BD' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*@`%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*@`D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*@`D' P=1:B solid*a3>Bfill.type<*@`D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*@a%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*@aD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*@aD' P=1:B solid*a3>Bfill.type<*@aD' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*@%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*@D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*@D' P=1:B solid*a3>Bfill.type<*@+Z   D] (  D D 0` ,$D 0 VH of breaking methane into it s original atoms (atomization) is experimentally determined to be 1660 KJ / mol2o(2aCGo$m D 0Xo ,$ 0 9C(2#( D 0䙛p,$  0 9H(2#( D 0袛0 ,$ 0 9H(2#( D 0 ,$  0 9H(2#( D 0p * ,$  0 9H(2#(B D@ s *Dpp,$D 0B  D@ s *Dp,$D  0B  D@ s *DpP00,$D  0B  D s *Dp00,$D  0B  D 0DPPVP ,$D  0  D 0T ,$@ 0 2Average bond enthalpy of C-H bond is therefore 1660 / 4 = 415 KJ / mol Experiments of other C-H containing molecules yield similar results.(2#'PP#'PP#'PPE#B D 0D) ,$D   0 D 0̛ =,$  0 HC (g) + 4H (g) 2# H D 0޽h ? 33MM___PPT10M.+邖@D0L' = @B DK' = @BA?%,( < +O%,( < +D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*Do%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*DoD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*DoD' P=1:B solid*a3>Bfill.type<*DoD0' =%(D' =%(D}' =A@BB1BB0B%()?D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*DD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*DD' =+4 8?HCBCBCBB*k3>'Bstyle.rotation<*DD' =-g6B fade*<3<*DD' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* D%(D' =-s6Bwipe(down)*<3<* DD' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* D%(D' =-s6Bwipe(left)*<3<* DD' =%(D3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* D%(D' =-o6Bwipe(up)*<3<* DD' =%(D9' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =-u6Bwipe(right)*<3<*DD' =%( D}' =A@BB1BB0B%()?D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*DD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*DD' =+4 8?HCBCBCBB*k3>'Bstyle.rotation<*DD' =-g6B fade*<3<*DD' =%( D' =A@BB1BB0B%())?)D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*DD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*DD' =+4 8?HCBCBCBB*k3>'Bstyle.rotation<*DD' =-g6B fade*<3<*DD' =%( D}' =A@BB1BB0B%()?D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*DD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*DD' =+4 8?HCBCBCBB*k3>'Bstyle.rotation<*DD' =-g6B fade*<3<*DD' =%(D}' =A@BB1BB0B%()?D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*DD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*DD' =+4 8?HCBCBCBB*k3>'Bstyle.rotation<*DD' =-g6B fade*<3<*DD' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*D%(D' =-s6Bwipe(left)*<3<*DDV' =%(D' =A@BBBB0B@HB%(D' =1:Bvisible*o3>+B#style.visibility<*D%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*DD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*DD' P=1:B solid*a3>Bfill.type<*DD ' =%(D' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* D%(D' =-s6Bwipe(down)*<3<* DD' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* D0%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* D0D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* D0D' P=1:B solid*a3>Bfill.type<* D0D]' =4@BBBB%(D' =,54PP*3>#Bstroke.color=@BPB<* DD' =1:B true*a3>Bstroke.on<* DD' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<* D0H%(D' =-g6B fade*<3<* D0HD' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* D0HD' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<* D0HD' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<* DH%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<* DHD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<* DHD' P=1:B solid*a3>Bfill.type<* DH+P+0+D ++0+D ++0+D ++0+D ++0+D ++0+D +F    He (  H H 0,$D 0 &.A Return to Hess s Law *Bond enthalpies can be used to determine heats of reactions Hrxn. *Allows us to see what causes a reaction to be endo. or exo.z(2# =#ck>ckZT1 H 0,$D 0 rBasic Concept Reactant + Reactant Product + Product`:(2'$NN' NN NN' NNB H s *D ,$@  0B H s *D ,$D  0 H 0 ` T ,$ 0 XEnergy required to Break Bonds(2$3 H 0h T ,$  0 ]#Energy released when new bonds form$(2$$3B H s *Dp ,$@   0B  H s *D ,$D   0  H 0p) T,$  0 HThe difference between the two determines endothermic versus exothermic.I(2I"  H s *A ??"`8 $D  0H H 0޽h ? 33;;___PPT10;.]h+R D:' = @B D:' = @BA?%,( < +O%,( < +D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*H%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*HD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*HD' P=1:B solid*a3>Bfill.type<*HD' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*H[%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*H[D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*H[D' P=1:B solid*a3>Bfill.type<*H[D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*H[%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*H[D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*H[D' P=1:B solid*a3>Bfill.type<*H[D' =%(D' =%(Dc' =4@BB/BB%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-g6B fade*<3<*HD' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*HD' =+4 8?bCB#ppt_y-.1BCB#ppt_yB*Y3>B ppt_y<*HD&' =%(D' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-s6Bwipe(down)*<3<*HD7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-s6Bwipe(down)*<3<*HD<' =%(D' =%(D' =A@BB(BB0B@ A%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-g6B fade*<3<*HD' =+4 8?bCB#ppt_x-.1BCB#ppt_xB*Y3>B ppt_x<*HD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*HD&' =%(D' =%(D7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-s6Bwipe(down)*<3<*HD7' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* H%(D' =-s6Bwipe(down)*<3<* HD<' =%(D' =%(D' =A@BB(BB0B@ A%(D' =1:Bvisible*o3>+B#style.visibility<*H%(D' =-g6B fade*<3<*HD' =+4 8?bCB#ppt_x-.1BCB#ppt_xB*Y3>B ppt_x<*HD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*HD?' =%(D' =%(D' =A@BB)BB0B@ A%(D' =1:Bvisible*o3>+B#style.visibility<* H%(DE' =+ 4 8?CB#ppt_xBCB#ppt_x+.1BCB#ppt_xB*Y3>B ppt_x<* HD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* HDM' =+4 8?CB#ppt_h/10BCB#ppt_h+.01BCB#ppt_hB*Y3>B ppt_h<* HDM' =+4 8?CB#ppt_w/10BCB#ppt_w+.01BCB#ppt_wB*Y3>B ppt_w<* HD' =+B#0,0; .5, 1; 1, 1-g6B fade*<3<* HDz' =%(D"' =%(D' =4@BB%BB%(D' =1:Bvisible*o3>+B#style.visibility<* H%(D' =-g6B fade*<3<* HD' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* HD-' =+4 8?hCB#ppt_y+1BCB#ppt_y-.03B*Y3>B ppt_y<* H)?DI' d=+4 8?dCB#ppt_y-.03BCB#ppt_yB*Y3>B ppt_y<* H%()?++0+H ++0+H ++0+ H +_ K0 `X0L(  L~ L s *P:4P   ~ L s *M4    L 0 Q P`$,$ 0 XNCH4 (g) + Cl2 (g) CH3Cl (g) + HCl (g)( 2'$NN/$NN '$NN/$NN'$NN$NN$NN$NN'$NN  L Zdb ?? ,$D 0 n Table 8.4 lists values of some bond energies. 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ZJ0 $0(0 'n#H L 0޽h ? 3eX{IZ(a___PPT10g.+D' = @B D' = @BA?%,( < +O%,( < +D' =%(DV' =%(D' =A@BBBB0B@HB%(D' =1:Bvisible*o3>+B#style.visibility<*L%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*LD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*LD' P=1:B solid*a3>Bfill.type<*LDC' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*L/%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*L/D-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*L/D' P=1:B solid*a3>Bfill.type<*L/DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*L/J%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*L/JD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*L/JD' P=1:B solid*a3>Bfill.type<*L/JDI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*LJn%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*LJnD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*LJnD' P=1:B solid*a3>Bfill.type<*LJn+8+0+L +EO   PT (  T T Z ?? p$D 0<4___PPT9 vIn this reaction, one C-H bond and one Cl-Cl bond must be broken. In turn, one C-Cl bond and one H-Cl bond are formed."w1 w#>'% T 0$$ XNCH4 (g) + Cl2 (g) CH3Cl (g) + HCl (g)( 2'$NN/$NN '$NN/$NN'$NN$NN$NN$NN'$NN  T c BAbondenthalpies"` ,$D 0B T@ s *D p ,$D  0B T@ s *Dp @ ,$D  0B T s *Dp ,$D   0B T s *D`@ ,$D   0  T c $A ??`= $D 0d  T 0A ?f;?"`  $D 0dB  T s *D)  ,$D 0  T rW?CalculationArial Black"`PL,$D 0  T c $A  ?? @   $@  0d T c $A  ??   $D  0dH T 0޽h ? 33AA___PPT10A.0\+^DoA' = @B D*A' = @BA?%,( < +O%,( < +D' =%(D' =%(D+' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-g6B fade*<3<*TD ' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*TB%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*TBD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*TBD' P=1:B solid*a3>Bfill.type<*TBD' =%(pD3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-o6Bwipe(up)*<3<*TD' =%(d D3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-o6Bwipe(up)*<3<*TDz' =%(D' =%(D5' =4@BBBB%(D' =-s6Bwipe(down)*<3<*TD' =1:Bhidden*o3>+B#style.visibility<*T%(D' =%(D5' =4@BBBB%(D' =-s6Bwipe(down)*<3<*TD' =1:Bhidden*o3>+B#style.visibility<*T%(D' =%(DI' =%(D' =4@BBBB@HB%(D' =1:Bvisible*o3>+B#style.visibility<*TBw%(DF' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*z3>!Bstyle.color= `B<*TBwD-' P=+4 8?pCB#333399 [5]BCB#009999 [6]B*a3>Bfillcolor<*TBwD' P=1:B solid*a3>Bfill.type<*TBwDv' =%(D' =%(D3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-o6Bwipe(up)*<3<*TD' =%(D3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-o6Bwipe(up)*<3<*TD' =%(D' =%(D5' =4@BBBB%(D' =-s6Bwipe(down)*<3<*TD' =1:Bhidden*o3>+B#style.visibility<*T%(DA' =%(D5' =4@BBBB%(D' =-s6Bwipe(down)*<3<*TD' =1:Bhidden*o3>+B#style.visibility<*T%(DR' =A@BB BB0B@%(D' =-g6B fade*<3<*TBD' =1:Bhidden*o3>+B#style.visibility<*TB%(DR' =A@BB BB0B@%(D' =-g6B fade*<3<*TBwD' =1:Bhidden*o3>+B#style.visibility<*TBw%(D"' =%( D' =4@BB%BB%(D' =1:Bvisible*o3>+B#style.visibility<* T%(D' =-g6B fade*<3<* TD' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* TD-' =+4 8?hCB#ppt_y+1BCB#ppt_y-.03B*Y3>B ppt_y<* T)?DI' d=+4 8?dCB#ppt_y-.03BCB#ppt_yB*Y3>B ppt_y<* T%()?DJ' =%( D' =4@BB"BB%(D' =1:Bvisible*o3>+B#style.visibility<* T%(D ' X=+4 . B(-#ppt_w/2)0B(#ppt_x)*Y3>B ppt_x<* T%(D' =+4 . B00B -1.0*[3>Bxshear<* T%(X))?)?D' =0l9 BBBBBB*<3<* T%(X))?)?D2' =+4 )B-(#ppt_h/3+#ppt_w*0.1)*Y3>B ppt_x<* T%(X))?)?D~' =%(D&' =%(Dc' =4@BBBB%()))D' =1:Bvisible*o3>+B#style.visibility<* T%(D' =-o6Bwipe(up)*<3<* TDc' =4@BBBB%()))D' =1:Bvisible*o3>+B#style.visibility<*T%(D' =-o6Bwipe(up)*<3<*TD' =%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<* T%(D' =-o6Bdissolve*<3<* TD' =%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<* T%(D' =-o6Bdissolve*<3<* T+8+0+T +3 0( h(  h h lA 4bondenthalpies"` ` <$D 0 d V h 0d   Notice: Only 1 C-H bond is broken on the left because C-H bonds appear as the same C-H bonds on the product side. Since these stay the same, there is no change in enthalpy associated with these. 2 h 0o"`   ,$D 0  h 0o"`  ,$D 0H h 0޽h ? 33  ___PPT10 .y+qTDW ' = @B D ' = @BA?%,( < +O%,( < +D' =%(D' =%(D+' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =-g6B fade*<3<*hDf' =%(D' =%(D+' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =-g6B fade*<3<*hD' =%(D+' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =-g6B fade*<3<* h+ d\t(  t t 0d PVrjb___PPT9D< Several Things to note: Equation must be balanced. Must draw Lewis Structures to see bonds between atoms. 3) To calculate bond enthalpy, simply determine how many and of what type of bonds are broken on the left and how many and of what type of bonds are formed on the right. Then calculate: Enthalpy of bonds broken  enthalpy of bonds formed. 4) A single C-C bond has a different enthalpy than a double C=C bond. (true for all elements). 5) Must look enthalpies up in tables. 6) If a coefficient appears in the equation before a compound, you must multiply that coefficient by the bonds broken or formed. Ex: 2CH4 = 8 CH bonds broken. = 6(414) KJp 2R 2 25 2R   " |8XH t 0޽h ? 3380___PPT10.yERI `X`X(  X X 04 X Homework 8.61-8.63, 8.65a, 8.66a!(2!"H X 0޽h ? 33___PPT10i. +D=' = @B + e]d(  d d 0d ` ]+Bond Enthalpies Can Be Found in Data Tables,(2,H d 0޽h ? 3380___PPT10.y0d -a 0 !@P(  Pd P <1?   P  `yjJjJ1?`  A2$0 # d P <1?`Pd P <1?P  P  T1 ?$     P  Zxaxa1 ?$ @    H P 0޽h ? a("xXMlU$:&MUETA*ԦU\xMĻzcSAEB UOJTVU.T*ؼykfS*Hh7o73+~IVCwiZ^MIl` ۂrs(ܑ.!*K%6_u׮_nSGa l$$e{l X%Hїw0wK@ļ*y&OSy(~7ݵqc_Hs/8X#}}o|7 Ź.pz8Xn3" CD,qE#N?n ;(8SC8]P{x=F3Ec?)N!CP5 E8w4nܬeͬM,.ih{GX*88α ѽ˾OO{zVO_bcYQtꬬV%!jLHt}Y:1BҔMV2 hՊlsS((za?ޑc}fyWtZ6I+w8й{ougߔwPO좚I+E-U=ĩ"?Ӝ 1xZUQ&<v$e͔ +0ݷj9{EMHL.IMuTU)h:i*T*rV:KO). 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K2 .1-Check your answers for Lewis Structures with v           .-@"Arial-. F2 A1*one another. Make sure you all come to a            .-@"Arial-. F2 T1*consensus of the correct answers for each.         .-@"Arial-.  2 k.-@"Arial-. ?2 k1%Make sure you handed in all homework n          .-@"Arial-. 62 ~1assignments from previous days.         .-@"Arial-.  2 .-@"Arial-. 12 1Go through the rest of this         .-@"Arial-. 2  Powerpoint   .-@"Arial-.  2 x..-@"Arial-.  2 .-@"Arial-. Q2 11Try your best on the homework at the end of this               .-@"Arial-. 2 1 Powerpoint   .-@"Arial-. B2 '. I will go over it in more detail in         .-@"Arial-. O2 10class on Monday. If you get stuck on any, save           .-@"Arial-. (2 1them for Monday and we     .-@"Arial-.  2 .-@"Arial-. 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